# What are the intercepts of 2x-13y=-17?

Sep 30, 2017

$\left(0 , \frac{17}{13}\right)$ and $\left(- \frac{17}{2} , 0\right)$

#### Explanation:

A y-axis intercept occurs on the axis when the x value is equal to 0. The same with the x-axis and the y value being equal to 0

So if we let x=0, we will be able to solve for the y value at the intercept.

$2 \left(0\right) - 13 y = - 17$
$- 13 y = - 17$
$y = \frac{- 17}{- 13}$
$y = \frac{17}{13}$

So the y-axis intercept occurs when x=0 and y=17/13 giving the co-ordinate.

$\left(0 , \frac{17}{13}\right)$

To find the x-axis intercept we do the same thing but let y=0.

$2 x - 13 \left(0\right) = - 17$
$2 x = - 17$
$x = - \frac{17}{2}$

The x-axis intercept occurs when y=0 and x=-17/2 giving the co-cordinate

$\left(- \frac{17}{2} , 0\right)$