What are the reactants in the equation $K_{2} S O_{4} + P b I_{2} \to P b S O_{4} + 2 K I$ $K_2SO_4 + PbI_2 -> PbSO_4 + 2KI$ ?

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Answer 1 · 2016-06-02T00:14:09

The reactants are $K_{2} S O_{4} and P b I_{2}$ $K_2SO_4 and PbI_2$
The products are $P b S O_{4} and K I$ $PbSO_4 and KI$

The reactants are on the left side of the equation.
The products are on the right side of the equation.

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What are the reactants in the equation K2SO4+PbI2→PbSO4+2KIK_2SO_4 + PbI_2 -> PbSO_4 + 2KI?