What are the y-intercepts of #2x+y^2=36 #?

1 Answer
Jul 9, 2016

The y intercepts are given when #x = 0#.

#2(0) + y^2 = 36#

#0 + y^2 = 36#

#y^2 = 36#

#y = +- 6#

Thus, there will be y intercepts at #(0, -6) and (0, 6)#.

The graph of the relation (this is not a function) confirms:

graph{2x + y^2 = 36 [-22.14, 22.15, -11.07, 11.07]}

Practice exercises:

  1. Determine the y intercepts of the following relations:

a) #x^2 + y^2 = 9#

b) #log_2(x + 2) = y#

c) #e^(4x) + 6 = y#

d) #2x + |x + 4| = y^2#

Hopefully this helps, and good luck!