What does #sin(arccos(6))-2csc(arcsec(9))# equal?

1 Answer
Mar 4, 2016

Undefined

Explanation:

The domain of the inverse of a function is the same as the range of the function. Then, as #arccos# is the inverse of cosine, the domain of #arccos# is equal to the range of #cos# which is #[-1, 1]#. As #6# lies outside that range, #arccos(6)# is undefined.

To see this without thinking about domain and range, just consider

#x = arccos(6)#

#=> cos(x) = cos(arccos(6)) = 6#

As #cos(x) in [-1, 1]# for all #x in RR# that means there is no such #x#, that is to say there is no value corresponding to #arccos(6)#