What element has the electron configuration #1s^(2)2s^(2)2p^(6)3s^(2)3p^(2)#?

1 Answer
Jan 18, 2016

Given that the element is neutral, and that there are 14 electrons, clearly #Z#, the atomic number #=# #14#.

Explanation:

If #Z# #=# #14#, the element is unequivocally indentified. Consult your handy Periodic Table.

It was given that there were 14 electrons. Given a neutral atom, there MUST be 14 positively charged particles in the element's nucleus. Thus #Z#, the atomic number, MUST be 14.

I'll give you a hint, the element's name starts with an #"S"#, hmm, sulfur, selenium, scandium??????