# What is bromine's electron configuration?

Jul 2, 2016

$B r = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10} 4 {p}^{5}$

$B r = \left[A r\right] 4 {s}^{2} 3 {d}^{10} 4 {p}^{5}$

#### Explanation:

Bromine is in the $4 t h$ energy level, $p$ block, $5 t h$ column, this means that the electron configuration will end $4 {p}^{5}$

$B r = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10} 4 {p}^{5}$

$B r = \left[A r\right] 4 {s}^{2} 3 {d}^{10} 4 {p}^{5}$