What is #int 4 x^5 -7 x^4 + 3 x^3 -8 x^2 -4 x + 1 dx#?
1 Answer
Jan 9, 2016
Explanation:
Use the power rule in reverse:
#intx^n# #dx=x^(n+1)/(n+1)+C#
Thus, the antiderivative of the function is
#4/6x^6-7/5x^5+3/4x^4-8/3x^3-4/2x^2+x+C#
which simplifies to be
#2/3x^6-7/5x^5+3/4x^4-8/3x^3-2x^2+x+C#
