What is #int x^4 + 9 x^3 -8 x^2 -3 x + 5 dx#?
1 Answer
Jan 21, 2016
Explanation:
Use the rule:
#intx^ndx=(x^(n+1))/(n+1)+C#
Also, recall that multiplicative constants (like the
Also, the antiderivative of a constant, like
The antiderivative of the given function is:
#x^(4+1)/(4+1)+(9x^(3+1))/(3+1)-(8x^(2+1))/(2+1)-(3x^(1+1))/(1+1)+(5x^(0+1))/(0+1)+C#
#=1/5x^5+9/4x^4-8/3x^3-3/2x^2+5x+C#