# What is the angular momentum of a rod with a mass of 2 kg and length of 9 m that is spinning around its center at 52 Hz?

Mar 8, 2017

The angular momentum is $= 4410.8 k g {m}^{2} {s}^{-} 1$

#### Explanation:

The angular momentum is $L = I \omega$

where $I$ is the moment of inertia

The moment of inertia of a rod, rotating about the center is

$I = \frac{1}{12} \cdot m {L}^{2}$

$= \frac{1}{12} \cdot 2 \cdot {9}^{2} = \frac{27}{2} k g {m}^{2}$

The angular velocity is

$\omega = 52 \cdot 2 \pi = 104 \pi r a {\mathrm{ds}}^{-} 1$

The angular momentum is

$L = I \omega = \frac{27}{2} \cdot 104 \pi = 4410.8 k g {m}^{2} {s}^{-} 1$