# What is the angular momentum of an object with a mass of 7 kg that moves along a circular path of radius 12 m at a frequency of  2/3 Hz ?

## I

Jan 29, 2016

$L = 1344 \setminus \pi N {s}^{-} 1$

#### Explanation:

Angular momentum of an object is $L = m v r$

Given that $m = 7 k g$, $r = 12 m$ and $\setminus \omega = 4 \setminus {\pi}^{c} / 3$ (They had given us linear frequency, not angular frequency)

They haven't given us $v$ directly. But, we know that $v = \setminus \omega r$, so let's get that into the angular momentum equation, which means
$L = m \setminus \omega {r}^{2}$

I'm sure you'll now understand how I got that $\setminus \pi$ there in the answer now.