Question

What is the antiderivative of `4/x^2`?

Answer 1

I found: `-4/x+c`

Explanation:

We can manipulate and integrate it to get:
antiderivative`=int4/x^2dx=int4x^-2dx=4intx^-2dx=`
`=4x^(-2+1)/(-2+1)+c=-4x^-1+c=-4/x+c`