What is the antiderivative of 4/x^2?

I found: $- \frac{4}{x} + c$
antiderivative$= \int \frac{4}{x} ^ 2 \mathrm{dx} = \int 4 {x}^{-} 2 \mathrm{dx} = 4 \int {x}^{-} 2 \mathrm{dx} =$
$= 4 {x}^{- 2 + 1} / \left(- 2 + 1\right) + c = - 4 {x}^{-} 1 + c = - \frac{4}{x} + c$