What is the antiderivative of #x^(1/2)#?

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Answer 1 · 2018-04-04T02:06:52

#(2x^(3/2))/3+C#

A simple rule:

#intx^ndx=(x^(n+1))/(n+1)# where #n# is a constant.

Therefore,

#intx^(1/2)dx=(x^(1/2+1))/(1/2+1)# Le'ts simplify this a bit.

#=>(x^(3/2))/(3/2)#

#=>(x^(3/2))*2/3#

#=>(2x^(3/2))/3# Do you #C# why this is incomplete?

#=>(2x^(3/2))/3+C# This is our answer!