What is the antiderivative of x^2?

2 Answers
May 23, 2018

It is x^3/3+C

Explanation:

Note that intx^ndx=x^(n+1)/(n+1)+C if n\ne -1

May 24, 2018

1/3x^3+C

Explanation:

The antiderivative of a function is the integral of that function. So here we have:

intx^2 \ dx

Using the rule that intx^n \ dx=(x^(n+1))/(n+1)+C,n!=-1, we find that it equals:

=(x^(2+1))/(2+1)+C

=1/3x^3+C