What is the antiderivative of #(x+4)^2#?

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Answer 1 · 2016-08-06T06:37:42

#int(x+4)^2 d x=1/3(x+4)^3+C#

#int (x+4)^2 d x=?#

#"Substitute "u=x+4#

#d u=d x#

#int(x+4)^2 d x=int u^2*d u#

#int u^2 *d u=1/3 u^3#

#int (x+4)^2 d x=1/3 u^3#

#"Undo substitution"#

#int(x+4)^2 d x=1/3(x+4)^3+C#