Question

What is the area below the curve `f(x)=x^3 -4x^2 +2x+ 8` and bounded by the y-axis, the x axis and x=3 expressed as an integral?

Answer 1

`S=69/4`

Explanation:

By definition of the integral such area is:

`int_0^3 (x^3-4x^2+2x+8)dx = [x^4/4-4x^3/3+2x^2/2+8x]_0^3` =

`81/4-36+9+24= 81/4-3=(81-12)/4=69/4`