What is the area of a triangle with sides of 39, 67.27 and 48.33 cm?

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Answer 1 · 2015-10-17T19:55:15

#sqrt(860255.971769)#.

You can use Heron's formula: if #a#, #b# and #c# are the sides of the triangle, then the area #A# can be found this way:

#A=sqrt(p * (p-a) * (p-b) * (p-c))#, where #p# is half of the perimeter: #{a+b+c}/2#.

So, let's compute #p#:

#(39+67.27+48.33)/2=77.3#.

So, the formula is

#sqrt(77.3 * (77.3-39) * (77.3-48.33) * (77.3 - 67.27))#

which is #sqrt(860255.971769)#.