# What is the area of a triangle with sides of 39, 67.27 and 48.33 cm?

##### 1 Answer
Oct 17, 2015

$\sqrt{860255.971769}$.

#### Explanation:

You can use Heron's formula: if $a$, $b$ and $c$ are the sides of the triangle, then the area $A$ can be found this way:

$A = \sqrt{p \cdot \left(p - a\right) \cdot \left(p - b\right) \cdot \left(p - c\right)}$, where $p$ is half of the perimeter: $\frac{a + b + c}{2}$.

So, let's compute $p$:

$\frac{39 + 67.27 + 48.33}{2} = 77.3$.

So, the formula is

$\sqrt{77.3 \cdot \left(77.3 - 39\right) \cdot \left(77.3 - 48.33\right) \cdot \left(77.3 - 67.27\right)}$

which is $\sqrt{860255.971769}$.