# What is the area of an equilateral triangle that has a side length of 4?

Dec 3, 2015

$A = 6.93$ or $4 \sqrt{3}$

#### Explanation:

$A = \frac{\sqrt{3}}{4} {a}^{2}$

a$\rightarrow$ side which $4$

$A = \frac{\sqrt{3}}{4} {4}^{2}$

$A = \frac{\sqrt{3}}{4} 16$

$A = \frac{16 \sqrt{3}}{4}$

$A = \frac{\cancel{4} \left(4\right) \sqrt{3}}{\cancel{4}}$

$A = 4 \sqrt{3}$

$\sqrt{3}$ $\rightarrow$ $1.73205080757$

$4 \sqrt{3} = 6.92820323028$

$A = 6.93$