What is the area of an equilateral triangle with side length 14?

1 Answer
Dec 1, 2015

#49sqrt3#

Explanation:

jwilson.coe.uga.edu

We can see that if we split an equilateral triangle in half, we are left with two congruent equilateral triangles. Thus, one of the legs of the triangle is #1/2s#, and the hypotenuse is #s#. We can use the Pythagorean Theorem or the properties of #30˚-60˚-90˚# triangles to determine that the height of the triangle is #sqrt3/2s#.

If we want to determine the area of the entire triangle, we know that #A=1/2bh#. We also know that the base is #s# and the height is #sqrt3/2s#, so we can plug those in to the area equation to see the following for an equilateral triangle:

#A=1/2bh=>1/2(s)(sqrt3/2s)=(s^2sqrt3)/4#

Since, in your case, #s=14#, the area of the triangle is #(14^2sqrt3)/4=(196sqrt3)/4=49sqrt3#.