What is the axis of symmetry and vertex for the graph y=2x^2-3x+8?

Jun 12, 2017

$V e r t e x \left(\frac{3}{4} , \frac{55}{8}\right)$

Explanation:

$y = 2 {x}^{\circ} - 3 x + 8$
x-coordinate of vertex, or of the axis of symmetry:
$x = - \frac{b}{2 a} = \frac{3}{4}$
y-coordinate of vertex:
$y \left(\frac{3}{4}\right) = 2 \left(\frac{9}{16}\right) - 3 \left(\frac{3}{4}\right) + 8 = \frac{9}{8} - \frac{9}{4} + 8 =$
$= - \frac{9}{8} + 8 = \frac{55}{8}$
$V e r t e x \left(\frac{3}{4} , \frac{55}{8}\right)$