# What is the axis of symmetry and vertex for the graph y = 2x^2 - 8x + 10?

##### 1 Answer
Apr 25, 2016

The axis of symmetry is $x = 2$ and vertex is at $\left(2 , 2\right)$

#### Explanation:

y=2x^2-8x+10 = 2(x^2-4x+4)+10-8=2(x- **2** )^2+ **2** The vertex is at (2,2)$\mathmr{and} t h e a \xi s o f s y m m e t r y i s$x=2# graph{2x^2-8x+10 [-10, 10, -5, 5]}[Ans]

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There is a problem with the [ 'double star'2'double star' ]. It messes up the auto formatting if included in non text string. I have tried often to get round this but in the end gave up.What should be written in your mathematical string is:

$y = 2 {x}^{2} - 8 x + 10 = 2 \left({x}^{2} - 4 x + 4\right) + 10 - 8 = 2 {\left(x - 2\right)}^{2} + 2$
The vertex is at $\left(2 , 2\right)$ and the axis of symmetry is $x = 2$