What is the axis of symmetry and vertex for the graph #y = 2x^2 - 8x + 10#?

1 Answer
Apr 25, 2016

The axis of symmetry is #x=2# and vertex is at #(2,2)#

Explanation:

#y=2x^2-8x+10 = 2(x^2-4x+4)+10-8=2(x- **2** )^2+ **2** The vertex is at #(2,2)# and the axis of symmetry is #x=2# graph{2x^2-8x+10 [-10, 10, -5, 5]}[Ans]

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#y=2x^2-8x+10 = 2(x^2-4x+4)+10-8=2(x- 2 )^2+ 2#
The vertex is at #(2,2)# and the axis of symmetry is #x=2#