What is the coefficient of #"O"_2# when the equation #"Mg"("ClO"_3)_2(s) -> "MgCl"_2(s)+"O"_2(g)# is balanced correctly using the smallest whole number coefficients?
1 Answer
Explanation:
You know that magnesium chlorate,
The unbalanced chemical equation that describes this decomposition reaction looks like this
#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + "O"_ (2(g))#
Now, you know that one formula units of magnesium chlorate contains
- one magnesium cation,
#1 xx "Mg"^(2+)# - two chlorate anions,
#color(blue)(2) xx "ClO"_3^(-)#
Since each chlorate anion contains
- two atoms of chlorine,
#color(blue)(2) xx 1 xx "Cl"# - six atoms of oxygen,
#color(blue)(2) xx 3 xx "O" = 6 xx "O"#
Notice that you have
The same can be said about chlorine since you have
Now, notice that you have a total of
You will now have
#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + 3"O"_ (2(g))#
Since