# What is the concentration of a solution prepared by diluting 20.0 mL of a .200 M NaCl to 250.0 mL?

May 28, 2016

$\text{Concentration" = "Amount of substance"/"Volume of solution}$

#### Explanation:

Thus $\text{Amount of substance"=" Concentration"xx"volume}$

$=$ $20.0 \times {10}^{-} 3 L \times 0.200 \cdot m o l \cdot {L}^{-} 1$ $=$ ??

This gives us the amount of sodium chloride dissolved in the initial volume. This is then redissolved in fresh solvent.

$\text{Concentration} = \frac{20.0 \times {10}^{-} 3 L \times 0.200 \cdot m o l \cdot {L}^{-} 1}{250.0 \times {10}^{-} 3 \cdot L}$ $=$ ??mol*L^-1.

The concentration is calculated with respect to $\text{NaCl}$.