What is the concentration of a solution prepared by diluting 20.0 mL of a .200 M #NaCl# to 250.0 mL?

1 Answer
anor277
May 28, 2016

#"Concentration" = "Amount of substance"/"Volume of solution"#

Explanation:

Thus #"Amount of substance"=" Concentration"xx"volume"#

#=# #20.0xx10^-3Lxx0.200*mol*L^-1# #=# #??#

This gives us the amount of sodium chloride dissolved in the initial volume. This is then redissolved in fresh solvent.

#"Concentration" =(20.0xx10^-3Lxx0.200*mol*L^-1)/(250.0xx10^-3*L)# #=# #??mol*L^-1#.

The concentration is calculated with respect to #"NaCl"#.

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