# What is the density and specific gravity of 250 mL of krypton gas with a mass of 0.934 g?

$\rho \cong 4 \cdot g \cdot {L}^{-} 1$
$\text{Density, "rho="Mass"/"Volume}$ $=$ $\frac{0.934 \cdot g}{0.250 \cdot L}$ $=$ ??g*L^-1.
$\text{Relative Density"=rho_"substance"/rho_"water}$, i.e. this is a dimensionless quantity. And ${\rho}_{\text{water}}$ $=$ $1.0 \cdot g \cdot m {L}^{-} 1$ under most circumstances.