What is the discriminant of #x^2+2x+8=0#?

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Answer 1 · 2014-09-11T05:27:03

Discriminant #->b^2-4ac#

#a=1#
#b=2#
#c=8#

#b^2-4ac->(2)^2-4(1)(8)#

#4-32=-28#

Because the Discriminant is less than 0 we know that we have 2 complex roots.

Please see the following link on how to find the discriminant.