What is the discriminant of $x^2+2x+8=0$ ?

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Answer 1 · 2014-09-11T05:27:03

Discriminant $->b^2-4ac$

$a=1$
$b=2$
$c=8$

$b^2-4ac->(2)^2-4(1)(8)$

$4-32=-28$

Because the Discriminant is less than 0 we know that we have 2 complex roots.

Please see the following link on how to find the discriminant.

What is the discriminant of x^2+2x+8=0x^2+2x+8=0?