# What is the distance between (0, 0, 8)  and (4, 3, 1) ?

Aug 22, 2016

The distance between $\left(0 , 0 , 8\right)$ and $\left(4 , 3 , 1\right)$ is $8.6023$

#### Explanation:

The distance between two points $\left({x}_{1} , {y}_{1} , {z}_{1}\right)$ and $\left({x}_{2} , {y}_{2} , {z}_{2}\right)$ is given by

$\sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}}$.

Hence distance between $\left(0 , 0 , 8\right)$ and $\left(4 , 3 , 1\right)$ is

$\sqrt{{\left(4 - 0\right)}^{2} + {\left(3 - 0\right)}^{2} + {\left(1 - 8\right)}^{2}}$

= $\sqrt{{4}^{2} + {3}^{2} + {\left(- 7\right)}^{2}}$

= $\sqrt{16 + 9 + 49}$

= $\sqrt{74} = 8.6023$