What is the distance between #(0, 0, 8) # and #(4, 3, 1) #?

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Answer 1 · 2016-08-22T18:20:16

The distance between #(0,0,8)# and #(4,3,1)# is #8.6023#

The distance between two points #(x _1,y_1,z_1)# and #(x _2,y_2,z_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#.

Hence distance between #(0,0,8)# and #(4,3,1)# is

#sqrt((4-0)^2+(3-0)^2+(1-8)^2)#

= #sqrt(4^2+3^2+(-7)^2)#

= #sqrt(16+9+49)#

= #sqrt74=8.6023#