What is the distance between #(1,3,-3)# and #(-2,1,-3)#?

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Answer 1 · 2016-08-23T14:35:11

The distance between #(1,3,-3)# and #(-2,1,-3)# is #3.6056#.

The distance between two points #(x _1,y_1,z_1)# and #(x _2,y_2,z_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#.

Hence distance between #(1,3,-3)# and #(-2,1,-3)# is

#sqrt((-2-1)^2+(1-3)^2+(-3-(-3))^2)#

= #sqrt((-3)^2+(-2)^2+0^2)#

= #sqrt(9+4+0)#

= #sqrt13=3.6056#