What is the distance between #(–10, –2, 2) # and #(4, –1, 2)#?

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Answer 1 · 2017-01-09T16:58:24

Distance between #(10,-2,2)# and #(4,-1,2)# is #6.083#.

The distance between two points #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# in three dimensional space is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Hence distance between #(10,-2,2)# and #(4,-1,2)# is

#sqrt((4-10)^2+(-1-(-2))^2+(2-2)^2)#

= #sqrt((-6)^2+(-1+2)^2+0^2)#

= #sqrt(36+1+0)#

= #sqrt37#

= #6.083#