What is the distance between #(2,15,7)# and #(2,4,-4)#?

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Answer 1 · 2016-06-05T06:27:37

The distance between #(2,15,7)# and #(2,4,-4)# is #15.5562#

In a two dimensional plane, distance between two points #(x_1,y_1)# and #(x_2,y_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

and in three dimensional space, distance between two points #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Hence, the distance between #(2,15,7)# and #(2,4,-4)# is

#sqrt((2-2)^2+(4-15)^2+(-4-7)^2)#

= #sqrt(0^2+(-11)^2+(-11)^2)=sqrt(0+121+121)=11sqrt2=15.5562#