What is the distance between #(2,15,7)# and #(2,4,-4)#?

1 Answer
Jun 5, 2016

Answer:

The distance between #(2,15,7)# and #(2,4,-4)# is #15.5562#

Explanation:

In a two dimensional plane, distance between two points #(x_1,y_1)# and #(x_2,y_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

and in three dimensional space, distance between two points #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Hence, the distance between #(2,15,7)# and #(2,4,-4)# is

#sqrt((2-2)^2+(4-15)^2+(-4-7)^2)#

= #sqrt(0^2+(-11)^2+(-11)^2)=sqrt(0+121+121)=11sqrt2=15.5562#