What is the distance between #(3,-12,12)# and #(-1,13,-12)#?

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Answer 1 · 2016-09-19T07:04:22

The distance betwen #(3,-12,12)# and #(-1,13,-12)# is #34.886#

In a three dimensional space, the distance between two points #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Hence, the distance betwen #(3,-12,12)# and #(-1,13,-12)# is

#sqrt(((-1)-3)^2+(13-(-12))^2+((-12)-12)^2)#

= #sqrt((-4)^2+(25)^2+(-24)^2)#

= #sqrt(16+625+576)#

= #sqrt1217#

= #34.886#