# What is the distance between (3, 4, 1)  and (0, 6, 0) ?

$\sqrt{14}$
We may solve this by using the normal Euclidean metric in ${\mathbb{R}}^{3}$ as follows :
d[(3,4,1);(0,6,0)]=sqrt((3-0)^2+(4-6)^2+(1-0)^2)
$= \sqrt{14}$