# What is the distance between (–4, 3, 0)  and (2, –3, 1) ?

Mar 24, 2016

$\sqrt{73}$

#### Explanation:

By making use of the normal Euclidean metric in ${\mathbb{R}}^{3}$ we get that
d[(-4,3,0);(2,-3,1)]=sqrt((-4-2)^2+(3-(-3))^2+(0-1)^2)

$= \sqrt{36 + 36 + 1}$

$= \sqrt{73}$