What is the distance between #(4, 4, 2)# and #(5, 6, 4) #?

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Answer 1 · 2018-03-15T09:33:19

The distance between #(4,4,2)# and #(5,6,4)# is #3# units.

We know that in a two dimensional Cartesian plane, distance between points #(x_1,y_1)# and #(x_2,y_2)# is

#sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

similarly in a three dimensional Cartesian space, distance between points #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# is

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Hence distance between #(4,4,2)# and #(5,6,4)# is

#sqrt((5-4)^2+(6-4)^2+(4-2)^2)#

= #sqrt(1+4+4)=sqrt9=3#