What is the distance between # (-6, -6) # and # (4,0) #?

1 Answer
May 28, 2018

Answer:

The distance is #2sqrt34# or about #11.66#.

Explanation:

The distance between two points is shown by the formula:
#d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)#

We have the values for the two coordinates, so we can substitute them into the distance formula:
#d = sqrt((0-(-6))^2 + (4-(-6))^2)#

And now we simplify:
#d = sqrt((6)^2 + (10)^2)#

#d = sqrt(36 + 100)#

#d = sqrt(136)#

#d = sqrt(4*34)#

#d = sqrt4sqrt34#

#d = 2sqrt34#

If you want the exact distance, you can leave it as #2sqrt34#, but if you want it in decimal form, it is #~~11.66# (rounded to nearest hundredth's place).

Hope this helps!