What is the distance between $(8,1,-4)$ and $(-3,6-2)$ ?

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Answer 1 · 2016-06-09T12:19:25

The distance between $(8,1,-4)$ and $(-3,6,-2)$ is $12.2475$

In a two dimensional plane, distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

and in three dimensional space, distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

Hence, the distance between $(8,1,-4)$ and $(-3,6,-2)$ is

$sqrt((8-(-3))^2+(1-6)^2+(-4-(-2))^2)$

= $sqrt(11^2+(-5)^2+(-2)^2)=sqrt(121+25+4)=sqrt150$

= $sqrt(2xx3xx5xx5)=5sqrt6=5xx2.4495=12.2475$

What is the distance between (8,1,-4)(8,1,-4) and (-3,6-2)(-3,6-2)?