What is the distance between #(8, 6, 2) # and #(3, 6, 2) #?

2 Answers
Apr 24, 2018

Answer:

5 units

Explanation:

We know the distance formula
d = #sqrt((x2-x2)^2+(y2-y1)^2+(z2-z1)^2) #
Therefore,
d = #sqrt((3-8)^2+(6-6)^2+(2-2)^2) #
d = #sqrt((-5)^2+(0)^2+(0)^2) #
d = #sqrt(25 #
d = 5 Units

Apr 25, 2018

Answer:

These only differ in one of the three coordinates, so the distance is the (absolute) difference between the remaining coordinate: #8-3# gives a distance of #5#.

Explanation:

This is my first answer where there's already another answer. I've been denoobed. Thanks, Socratic!