# What is the distance between (8, 6, 2)  and (3, 6, 2) ?

Apr 24, 2018

5 units

#### Explanation:

We know the distance formula
d = $\sqrt{{\left(x 2 - x 2\right)}^{2} + {\left(y 2 - y 1\right)}^{2} + {\left(z 2 - z 1\right)}^{2}}$
Therefore,
d = $\sqrt{{\left(3 - 8\right)}^{2} + {\left(6 - 6\right)}^{2} + {\left(2 - 2\right)}^{2}}$
d = $\sqrt{{\left(- 5\right)}^{2} + {\left(0\right)}^{2} + {\left(0\right)}^{2}}$
d = sqrt(25
d = 5 Units

Apr 25, 2018

These only differ in one of the three coordinates, so the distance is the (absolute) difference between the remaining coordinate: $8 - 3$ gives a distance of $5$.