What is the distance, in units, between (–2, 8) and (–10, 2) in the coordinate plane?

Mar 26, 2018

The distance is 10 units.

Explanation:

distance between $A \left({x}_{1} , {y}_{1}\right) \mathmr{and} \left({x}_{2} , {y}_{2}\right)$ on xy plane:

$d = \sqrt{{\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2}} = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2}}$

$d = \sqrt{{\left(- 2 - \left(- 10\right)\right)}^{2} + {\left(8 - 2\right)}^{2}}$

$d = \sqrt{100} = 10$