What is the electric current produced when a voltage of #15 V# is applied to a circuit with a resistance of #6 Omega#?

2 Answers
Mar 10, 2018

Answer:

#2.5 amperes#

Explanation:

The formula needed to solve this question is defined by Ohms Law

#V=IR#

Which we can rearrange to find the current

#I=V/R#

Where

#I# = Current (#amperes#)
#R# = Resistance (#ohms#)
#V# = Potential Difference (#vol#t#s#)

Substitute in the values you already have into the formula

#I#=#15/6#

#:.# #I = 2.5 amperes#

Mar 11, 2018

Answer:

#2.5 \ "A"#

Explanation:

We use Ohm's law here, which states that

#V=IR#

where #V# is the voltage, #I# is the current in amperes, and #R# is the resistance in ohms.

We need to solve for current, so we can rearrange the equation into

#I=V/R#

Plugging in the given values, we get

#I=(15 \ "V")/(6 \ Omega)#

#=2.5 \ "A"#

So, the electric current has a strength of #2.5# amperes.