What is the electric current produced when a voltage of #8 V# is applied to a circuit with a resistance of #16 Omega#?

1 Answer
Jan 12, 2016

Answer:

#I=0.5 A= 500 mA#

Explanation:

The Ohm's Rule is:

#R=V/I#

#:.I=V/R#

In this case:

#V= 8 V#
#R=16 Omega#

then

#I= cancel(8)^1/cancel(16)^2=1/2=0.5 A#

With A= Ampere measurement unit of I

Sometimes, in Electronic, is usally expressed as #[mA]#

#1mA=10^-3A#

#:.I=0.5 A= 500 mA#