Question

What is the electron configuration for nickel, whose atomic number is 28?

Answer 1

`Ni = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^8`

`Ni = [Ar] 4s^2 3d^8`

Explanation:

Nickel is in the `4th` energy level, `d` block, `7th` column, this means that the electron configuration will end `3d^8` with the `d` orbital being one level lower than the energy level it is on.

`Ni = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^8`

`Ni = [Ar] 4s^2 3d^8`