# What is the electron configuration for the silicon atom?

Jan 8, 2018

$\left[N e\right] 3 {s}^{2} \setminus 3 {p}^{2}$

#### Explanation:

Silicon has an atomic number of $14$, so a neutral silicon atom would have $14$ electrons.

Therefore, it would have enough electrons to fill up till its $3 p$ shell.

Its electron configuration would be

$1 {s}^{2} \setminus 2 {s}^{2} \setminus 2 {p}^{6} \setminus 3 {s}^{2} \setminus 3 {p}^{2}$

We know that neon is a noble gas with an electron configuration of
$1 {s}^{2} \setminus 2 {s}^{2} \setminus 2 {p}^{6}$.

So, we can shorten silicon's electron configuration to a noble-gas configuration, which would be

$\left[N e\right] 3 {s}^{2} \setminus 3 {p}^{2}$