# What is the electron configuration of Ag?

##### 2 Answers

The electron configuration for silver (Ag) is based upon the place meant of silver in the fifth row of the periodic table in the 11th column of the periodic table or the 9th column of the transition metal or d block. Therefore th electron configuration for silver must end as

This notation can be written in core notation or noble gas notation by replacing the

For some of the transition metals they will actually transfer an s electron to complete the d orbital, making silver,

I hope this was helpful.

SMARTERTEACHER

#### Answer:

#### Explanation:

*Silver*,

This tells you that a *neutral* silver atom will have a total of

Now, you have to be a little careful with silver because it is a *transition metal*, which implies that the occupied **d-orbitals** are actually *lower in energy* than the **s-orbitals** that belong to the highest energy level.

So, here's how silver's electron configuration would look if it followed the *Aufbau principle* to the letter

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(blue)(4s^2 4p^6) color(red)(3d^10) 5s^2 4d^9#

Now, for the energy level **d-orbitals** that belong to the *lower in energy* than the s and p orbitals that belong to the

This means that you will have to switch the **3d** orbitals on one hand, and the **4s** and **4p** orbitals on the other.

This will get you

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 5s^2 4d^9#

Now do the same for the **4d** and **5s** orbitals

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 4d^9 5s^2#

The thing to remember here is that in silver's case, the **4d** orbitals will be **completely filled**. That implies that you won't have two electrons in the **5s** orbital, since one will be kept in the lower 4d orbitals.

This means that the electron configuration of silver will be

#"Ag: " 1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6) 4d^10 5s^1#

Using the noble gas shorthand notation will get you

#"Ag: " overbrace(1s^2 2s^2 2sp^6 3s^2 3p^6 color(red)(3d^10) color(blue)(4s^2 4p^6))^(color(green)(["Kr"])) 4d^10 5s^1#

#"Ag: " ["Kr"] 4d^10 5s^1#