Question

What is the electron configuration of `Cu^+`?

Answer 1

Well we got copper, `Z=29`.........

Explanation:

And thus for the `"cuprous ion"`, `Cu^+`, we gots 28 electrons to distribute:

`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)`

And for the `"cupric ion"`, `Cu^(2+)`, we gots 27 electrons to distribute:

`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(9)`