What is the electron configuration of Li+?

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What is the electron configuration of Li+?

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Answer 1 · 2016-02-01T01:56:50

$Li^{+} : 1 s^{2}$ $"Li""^(+): 1s^2$

Explanation:

Your starting point here will be the electron configuration of a neutral lithium atom, $Li$ $"Li"$ .

A quick look in the periodic table will reveal that lithium is located in period 2, group 1, and that it has an atomic number equal to $3$ $3$ .

This means that a neutral lithium atom will have a total of $3$ $3$ electrons surrounding its nucleus.

![http://www.chemizzle.com/p/http://electron-configuration.html](https://useruploads.socratic.org/lmuGs86SuiDmTU8l7OAc_Electron%20Diagram.PNG)

Its electron configuration will be

$Li: 1 s^{2} 2 s^{1}$ $"Li: " 1s^2 color(red)(2)s^1$

Now, the lithium cation, ${Li}^{+}$ $"Li"^(+)$ , is formed when lithium loses the electron located on its outermost shell $\to$ $->$ its valence electron. This electron is located on the second energy level, in the 2s-orbital.

This means that the electron configuration of the ${Li}^{+}$ $"Li"^(+)$ cation will be

${Li}^{+} : 1 s^{2}$ $"Li"^(+): 1s^2$

To write this using noble gas shorthand notation, use the electron configuration of the noble gas that comes before lithium in the periodic table.

Helium, $He$ $"He"$ , has the electron configuration

$He: 1 s^{2}$ $"He: " 1s^2$

This means that you have

${Li}^{+} : [He]$ $"Li"^(+): ["He"]$

Here the notation $[He]$ $["He"]$ is meant to represent the electron configuration of helium.

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What is the electron configuration of Li+?

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