What is the electron configuration of Platinum?

Jun 26, 2016

This is an unusual configuration.

Explanation:

$P t , Z = 78$

$\left[X e\right] 4 {f}^{14} 5 {d}^{9} 6 {s}^{1}$

The lower transition metals (and some of the first row, (i.e. $C r$, $C u$) tend to have non-canonical electron configurations. For platinum, so I am told, this is a relativistic effect (whatever that is!).

Most of the time we deal with $P {t}^{2 +}$, a diamagnet, though $P {t}^{0}$ complexes also tend to be diamagnetic. Depending on your prof, if you wrote $\left[X e\right] 4 {f}^{14} 5 {d}^{10}$ you would probably be given full marks.