Question

What is the electron configuration of Sc+3?

Answer 1

You got scandium...`Z=21`, i.e. 18 electrons to distribute in the trication.

Explanation:

And so we follow the usual `"Aufbau scheme"`...

`underbrace(1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^1)_"electronic configuration of scandium metal"`

`underbrace(1s^(2)2s^(2)2p^(6)3s^(2)3p^(6))_"electronic configuration of scandium trication"`