What is the electron configuration of the oxide ion $O^{2 -}$ $O^(2-)$ ?

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Answer 1 · 2017-02-18T03:56:31

It is isoelectronic with $"neon"........$

For oxygen, $Z=8$ , and thus $O^(2-)$ has a configuration of:

$1s^(2)2s^(2)2p^6$ , i.e. 10 electrons distributed..........why?

What is the electron configuration of the oxide ion O^(2-)O2−O^(2-)?