# What is the electron geometry and molecular geometry for CH_4?

And therefore, the electronic geometry will be tetrahedral. Since all of these electron pairs represent $C - H$ bonds, the molecular geometry will also be tetrahedral with $\angle H - C - H = {109.5}^{\circ}$. Would the same geometry pertain to ammonium ion, $N {H}_{4}^{+}$? Why or why not?