# What is the electronic configuration of a 6+ chromium ion?

$Z$ for Cr is 24. $C r \left(V I\right)$ therefore has 18 electrons to distribute
$C r$ metal is $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{1} 3 {d}^{5}$
$C r \left(V I\right)$ has all the valence electrons removed; 18 electrons to distribute, i.e. $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6}$