Question

What is the equation of the circle with a center at `(5 ,-3 )` and a radius of `2`?

Answer 1

I found: `x^2+y^2-10x+6y+30=0`

Explanation:

We can use the general equation:
`color(red)((x-h)^2+(y-k)^2=r^2)`
Where `h,k` are the coordinates of the center and `r` is the radius. So you get:
`(x-5)^2+(y+3)^2=2^2`
`x^2-10x+25+y^2+6y+9=4`
`x^2+y^2-10x+6y+30=0`