What is the equation of the circle with a center at #(-8 ,-7 )# and a radius of #4 #?
1 Answer
Jan 26, 2016
Explanation:
The standard form of a circle with a center at
#(x-h)^2+(y-k)^2=r^2#
Since the center is
#{(h=-8),(k=-7),(r=4):}#
Thus, the equation of the circle is
#(x-(-8))^2+(y-(-7))^2=4^2#
This simplifies to be
#(x+8)^2+(y+7)^2=16#